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6/2(2+1)=???

6/2(2+1)=???

there's a wiki about why alot people talking about 1 or 9, before it was 1, it just looks like the formula what i typed, 2 have to * 3 to make it to 6 and 6 / 6 = 1. but after someone finds out it will goes to "6 / 2 x 3 = 3 x 3 = 9.
idk how to talk about this
well 1 isn't right cuz ur suppose to go left to right
 
well 1 isn't right cuz ur suppose to go left to right
it was before, after someone posted because they ignores 6 / 2 "x" (2+1), so if they ignored, it would be 1, but if they didnt, it will be 6 / 2 x 3 = 3 x 3 = 9.
 
Brackets go first so
6/2(3)
6/6
1
No, brackets won't go first becauses the bracket is a multiication and theres no equation inside the brackets so u do it left to right so the divide first then mutliplaciation
 
If you do brackets first, the answer is never 9.
6/2(1+2)
6/2(3)
6/6
1

Here is where you said it.


Brackets go first so
6/2(3)
6/6
1
Brackets go first.
6/2(1+2)
6/2(3)
Now, 6/2(3) is the exact same thing as 6/2*3.
Nowadays the standard is to do whichever operation comes first (if it's multiplication or division).
Therefore we have:
6/2*3
3*3
9
 
No, brackets won't go first becauses the bracket is a multiication and theres no equation inside the brackets so u do it left to right so the divide first then mutliplaciation
It doesn't matter how you get rid of the brackets. And also try this:

Replace (1+2) with x
Then you get 6/2x
Keep in mind x=3
If 6/2x=9
then 6=18x
1/3=x

1/3 can't be x since x is already equal to 3
 
Brackets go first.
6/2(1+2)
6/2(3)
Now, 6/2(3) is the exact same thing as 6/2*3.
Nowadays the standard is to do whichever operation comes first (if it's multiplication or division).
Therefore we have:
6/2*3
3*3
9
a better look version, just people ignores "*" and it will goes to 1.
 
Brackets go first.
6/2(1+2)
6/2(3)
Now, 6/2(3) is the exact same thing as 6/2*3.
Nowadays the standard is to do whichever operation comes first (if it's multiplication or division).
Therefore we have:
6/2*3
3*3
9
exactly that stupid cake noob saying 6/2(3) THE 2x3 SHOULD GO FIRST the def failed 5th grade math
 
exactly that stupid cake noob saying 6/2(3) THE 2x3 SHOULD GO FIRST the def failed 5th grade math
That's ironic.

6/2(3)
2(3) is ONE value thats why you divide it like this
6
----
2(3)

6
--- = 1
6

If you divide first, you contradict an infinite amount of algebraic functions.
 
It doesn't matter how you get rid of the brackets. And also try this:

Replace (1+2) with x
Then you get 6/2x
Keep in mind x=3
If 6/2x=9
then 6=18x
1/3=x

1/3 can't be x since x is already equal to 3
you literally just used another way of doing ur wrong math equation
 
That's ironic.

6/2(3)
2(3) is ONE value thats why you divide it like this
6
----
2(3)

6
--- = 1
6
that's before people found the answer, the newest answer is they ignored 6 / 2 "*" 3, they missed * so it could be 1, if they added it to make 2 x (3) it would be 9
 
You still haven't responded to my function where we replace (1+2) with x
This is also exactly how functions are made.
6/2x=1
6=2x
3=x

If the answer is 1, then the algebraic expression also becomes true.

2(1+2) is one value and will remain 1 value.

were u borned in the 1917?
Math doesn't change like this.
I was also taught the 1917 order of operations, although our textbooks use a fraction sign which is far more superior to the stupid division symbol. Also the division symbol was designed to divide one side by the other, kind of like the fraction symbol.

This one statement is true and will remain true:
First X÷Y(a+b) is not equal to (X/Y)(a+b). Here, X÷Y(a+b) = X÷(Ya+Yb) If its (X÷Y)(a+b) then it's equal to (X/Y)(a+b). Those who still think the ans is 9 then first learn the difference between X÷Y(a+b) and (X÷Y)(a+b).
 
You still haven't responded to my function where we replace (1+2) with x
This is also exactly how functions are made.
6/2x=1
6=2x
3=x

If the answer is 1, then the algebraic expression also becomes true.

2(1+2) is one value and will remain 1 value.


Math doesn't change like this.

This one statement is true and will remain true:
First X÷Y(a+b) is not equal to (X/Y)(a+b). Here, X÷Y(a+b) = X÷(Ya+Yb) If its (X÷Y)(a+b) then it's equal to (X/Y)(a+b). Those who still think the ans is 9 then first learn the difference between X÷Y(a+b) and (X÷Y)(a+b).
i cant help someone that doesnt help themselves
 
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